GET Android 摸拟器 IP.

简单做了一个android的project

想能过以下代码取得摸拟器的IP:

public String getLocalIpAddress()  {      try      {          for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();)          {             NetworkInterface intf = en.nextElement();             for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();)             {                 InetAddress inetAddress = enumIpAddr.nextElement();                 if (!inetAddress.isLoopbackAddress())                 {                     return inetAddress.getHostAddress().toString();                 }             }         }      }      catch (SocketException ex)      {          //Log.e(S.TAG, ex.toString());      }      return null; }

运行结果,为NULL,百思不得其解,

尝试方法二:

try {    Socket socket = new Socket("www.droidnova.com", 80);    Log.i("", socket.getLocalAddress().toString());} catch (Exception e) {    Log.i("", e.getMessage());}

同样无解.晕

万事,还真是开头难.

找STORM哥帮手:

修改XML如下:

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.test.main"
android:versionCode="1"
android:versionName="1.0">
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".hello"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>

</application>
<uses-sdk android:minSdkVersion="8" />

<uses-permission android:name="android.permission.INTERNET"></uses-permission>
</manifest>

重点在红色部分.解决,记录

更多相关文章

随机推荐