Android之获取Android唯一ID

//获得独一无二的Psuedo ID    private static String getUniquePsuedoID() {        String serial = null;        String m_szDevIDShort = "35" +                Build.BOARD.length() % 10 + Build.BRAND.length() % 10 +                Build.CPU_ABI.length() % 10 + Build.DEVICE.length() % 10 +                Build.DISPLAY.length() % 10 + Build.HOST.length() % 10 +                Build.ID.length() % 10 + Build.MANUFACTURER.length() % 10 +                Build.MODEL.length() % 10 + Build.PRODUCT.length() % 10 +                Build.TAGS.length() % 10 + Build.TYPE.length() % 10 +                Build.USER.length() % 10; //13 位        try {            serial = android.os.Build.class.getField("SERIAL").get(null).toString();            //API>=9 使用serial号            return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();        } catch (Exception exception) {            //serial需要一个初始化            serial = "serial"; // 随便一个初始化        }        //使用硬件信息拼凑出来的15位号码        return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();    }

结果：00000000-7dc2-f1aa-ffff-fffff6f7ee5d

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